日本最麻烦就是生产系统,各种资源的换算方式如下:
9 Q( ?5 A, o1 y( ]9 F$ ]3 C+ z
3 B) }6 y, c4 \+ D2 }( @2 W" {Resource:
! L$ n+ j# O) Z- O* a; b1 resource center 产生1.25 resource point+1 supply point
7 d! V9 Z* D5 E: n# Y+ X5 P1 oil center产生6 oli point + 1 fuel point
' l/ q9 S6 _$ DManpower:# ]' M5 W$ I1 n5 H' Y- ]8 A
10 resource point 激活 1 manpower center,并且消耗10 resource point 产生5 manpower入pool" H+ A$ K2 E7 G* l0 x! ~
Heavy Industry:3 P' r/ ?1 v" M" d* i
1 resource point+2 oil point 激活 1 HI factory
+ z+ h% ]( C, S% P0 {3 Y1 HI消耗 1resource point+1 oil point 产生 1supply point+ 1.33 fuel point" R Q- K1 p1 B0 O
同时与HI factory同数量的HI入HI pool,并消耗与HI point 相同的 resource point+2x HI的oil point. ]! M$ {1 O, s; n
Engine factory:
' _4 c7 @. X! |8 h4 W只有当地每天产生的HI至少等于engine factory时,才能激活engine factory,每天产生的engine=engine factory + RN(1-30)/30,同时每产生1 engine消耗18HI* I5 v, o) y) c% q( F3 L
Vehicle factory:# X+ W% g( m4 Q' D6 n1 G7 C
1 vehicle factory 需要6HI激活,同时消耗1HI产生1vehicle point入pool
) Z9 g' x6 B2 g# q, j' M( D1 vehicle point+1manpower point 产生1 land cost6 n7 b7 D% j( l! Y: |9 B+ I: B; W
Armament factory:
7 Q* D; E3 t" F0 n$ R1 HI激活1 armament factory,并且消耗6Hi产生1 armament point
1 S3 T& x A, h' |% g1 armament point+1 manpower point产生1 load cost(非vehicle unit)
0 F2 O: |4 x8 L X2 }- e) n3 }0 {$ AShipyards:
) i0 O, C H) a! R8 e2 G1 shipyard 消耗3 HI产生1 shipyard point。
0 l0 l9 x9 I9 f& ~. z新ship 增援时间提前一天,就多消耗与ship durability 同等数量的shipyard point. |